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 The Ionization Potentials and Shielding of the Eight Electrons in the Third Shell

The Bohr model of a hydrogen-like ion predicts that the total energy E of an electron is given by

#### E = −Z²R/n²

where Z is the net charge experienced by the electron, n is the principal quantum number and R is a constant equal to approximately 13.6 electron volts (eV). This formula is the result of the total energy being equal to

#### E = − Ze²/(2rn)

where e is the charge of the electron and rn is the orbit radius when the principal quantum number is n. The orbit radius is given by

#### rn = n²h/(Zmee²)

where h is Planck's constant divided by 2π and me is the mass of the electron.

## Shell Structure

Electrons in atoms are organized in shells whose capacities are equal to 2m², where m is an integer. Thus there can be at most 2 electrons in the first shell, 8 in the second shell, 8 in the third shell and 18 in each of the fourth and fifth shells. Here only the third shell is being considered.

Here are all the ionization potentials for such ions. The values are for the elements for which the data is available in the CRC Handbook of Physics and Chemistry 82nd Edition (2001-2002).

## The Ionization Potential of the First Electron as a Function of Proton Number

An ion with only one electron in a shell is equivalent to the hydrogen atom but having a positive charge of Z instead of one, where Z is the proton number #p of the nucleus less the amount of shielding by the electrons in the inner shells. The Bohr theory applies to such system. According to the Bohr theory the ionization potential should be

#### IE = (R/n²)(#p−ε)²

Where R is constant known as the Rydberg constant and is equal to about 13.6 electron volts (eV), n is the principal quantum number which here is the same as the shell number. The quantity #p is the proton number of the nucleus and ε is the amount of shielding by electrons in inner shells or the same shell. For the first electron in the third shell it is usually presumed that the ten electrons in the first and second shell shield exactly ten units of charge. It is immediately discovered that this not the case. Here is the plot of the relationship for the first electron.

This appears to be a quadratic relationship but shifted; i.e. something proportional to (#p−ε)². Thus equation is then

#### IE = (R/n²)(#p−ε)²which can be expressed as IE = (R/n²)(#p² − 2#p*ε + ε²)

The appropriate regression equation would be

#### IE = c0 + c1#p + c2(#p)² in which c1<0

The regression results are

#### IE = 100.2997005 − 25.85023387#p + 1.569793906 (#p)² [42.8] [-130.3] [380.6] R² = 0.999999245

The numbers in the square brackets are the t-ratios for the regression coefficients. For a regression coefficient to be statistically significantly different its magnitude must be greater than 2.0. As can be seen the regression coefficients for are highly significant.

The value of ε can be found as

#### ε = ½(−c1/c2) = 8.233639386

Thus the shielding of the first electron in the third shell by the ten electrons in the first and second shells is not exactly 10. Instead it is about 82.3 percent of that value. This could be due to the distributions of the charges of the two inner electrons, either their radial dispersion or their asymmetry.

The regression results for all eight of the electrons in the third shell are

 Number ofElectronsin Shell Shieldingε ConstantR Coefficient of DeterminationR² 1 8.233639386 14.12814515 0.999999245 2 8.850059478 14.20186513 0.999999245 3 9.566613526 13.63683417 0.999698201 4 11.01955101 14.6263037 0.999573295 5 11.192554745 14.10977023 0.999999218 6 11.96012806 13.99266234 0.999998189 7 12.6053219 14.03815118 0.999997968 8 13.52918132 14.47872006 0.999993592

The graph of the shielding versus the number of electrons in the shell is:

The slope of the relationship is found by regressing the shielding S on the number of electrons #e. This gives

#### S = 7.483989055 + 0.752364916#e [39.6] [20.1] R² = 0.985388779

Thus, on average, each additional electron in the second shell shields about 0.752 units of positive charge of the nucleus.

## Conclusions

The values of the ionization potentials IE are accurately explained by a function of the form

#### IE = (R/n²)(#p−ε)²

where R is an empirical constant approximately equal to the Rydberg constant, n is the shell number, #p is the proton number of the nucleus, and ε is an empirical value which is a function of the number of electrons in the shell and the number which are in inner shells.

(To be continued.)